Custom label for a numbered list

Questions
,
1

Hello,

I am trying to build a numbered list for k-steps.
The main idea is that the numbering begins at 1, at some points becomes an empty value, then the final value is labels as a k.

I try to use the #enum function with the enum.item, but it does not seem to work with letters or the none value.

My current code looks like this:

 the following $k$ steps are perform:
+ sample $theta_1^{d+1}$ from $"p" ( theta_1|theta_2^d, dots.h.c  , theta_k^d, y )$,
+ sample $theta_2^{d+1}$ from $"p" (theta_2|theta_1^{d+1}, theta_3^{d}, dots.h.c, theta_{k}^d, y)$, 
+ $dots.h.c$ // there should be number in this step
+ sample $theta_k^{d+1}$ from $"p" (theta_k| theta_1^{d+1}, theta_2^{d+1}, dots.h.c, theta_{k-1}^{d},y ).$ // This label should be "k"

Thank you in advance!

2

Here’s one way of doing it:

#show enum: it => {
  //If this enum has already been processed, don't process it again
  if it.has("label") and it.label == <already-processed> {return it}
  
  //Get the total number of items and only apply this to lists with 3 or more items
  let num-items = it.children.len()
  if num-items < 3 {return it}
  
  //Define the conditions for displaying a "k" and ""
  let fancy-numbering = n => if n == num-items {
    "k"
  } else if n == num-items - 1 {
    ""
  } else {
    n
  }

  //Create a new list and add a label to it that it has been processed
  [#enum(
    tight: it.tight,
    numbering: fancy-numbering,
    full: it.full,
    indent: it.indent,
    body-indent: it.body-indent,
    spacing: it.spacing,
    number-align: it.number-align,
    
    ..it.children.map(child => enum.item(none, child.body))
  )<already-processed>]
}

the following $k$ steps are perform:
+ #lorem(5)
+ #lorem(5)
+ $dots.h.c$
+ #lorem(5)

image
image511×234 18.2 KB

It seems to me though, that adding the ellipsis between the 2 and k would also be nice. For that, change the second conditional line to this:

  } else if n == num-items - 1 {
    sym.dots.v //was ""
  }

image
image511×234 17.9 KB

2 Likes
3

Hello,
Is there now an easier way to do this? the current solution does not seem to work in the latest version of typst (or at least not for me)

4

What’s your version?

Try

#sys.version
5

Hello,
It is 0.14.2

6

For the future, some more details about how it isn’t working would be nice.

The error is here:

image
image537×166 22.1 KB

Fixing it is simple, simply remove the none, so that child.body is the only argument:

..it.children.map(child => enum.item(child.body))

It seems the enum.item documentation is out of date because it lists two parameters.

Edit: Full code that works with `0.14.2` 
#show enum: it => {
  //If this enum has already been processed, don't process it again
  if it.has("label") and it.label == <already-processed> {return it}
  
  //Get the total number of items and only apply this to lists with 3 or more items
  let num-items = it.children.len()
  if num-items < 3 {return it}
  
  //Define the conditions for displaying a "k" and ""
  let fancy-numbering = n => if n == num-items {
    "k"
  } else if n == num-items - 1 {
    sym.dots.v
  } else {
    n
  }

  //Create a new list and add a label to it that it has been processed
  [#enum(
    tight: it.tight,
    numbering: fancy-numbering,
    full: it.full,
    indent: it.indent,
    body-indent: it.body-indent,
    spacing: it.spacing,
    number-align: it.number-align,
    
    ..it.children.map(child => enum.item(child.body))
  )<already-processed>]
}

the following $k$ steps are perform:
+ #lorem(5)
+ #lorem(5)
+ #none
+ #lorem(5)
1 Like
7

The first argument of type auto/int is optional, it does not allow none anymore. 0.14.0 – Typst Documentation

2 Likes