Hi, everyone. I found that my long equation overlaps with the equation numbering. How could I address this problem? Thank you.
#set heading(numbering: "1.1")
#set par(justify: true)
#set page(numbering: "1 of 1")
#set math.equation(numbering: (..nums) => {
let section = counter(heading).get().first()
numbering("(1.1)", section, ..nums)
})
#show heading.where(level: 1): it => {
counter(math.equation).update(0)
it
}
#show ref: it => {
let eq = math.equation
let el = it.element
if el != none and el.func() == eq {
// Override equation references.
"expression "
numbering(
el.numbering,
..counter(eq).at(el.location())
)
} else {
// Other references as usual.
it
}
}
#import "@preview/glossarium:0.5.1": make-glossary, register-glossary, print-glossary, gls, glspl
#show: make-glossary
$
PP[(s_a,r_a),(s_b,r_b)] &= frac(PP_("incr")(L_a,L_b)^N, PP_("incr")(L_a,L_b)^N + PP_("incr")(L_b,L_a)^N) \
&= frac([1/4 B(u_S (s_a),u_S (s_b)) + 1/4 B(u_R (r_a),u_R (r_b))]^N,[1/4 B(u_S (s_a),u_S (s_b)) + 1/4 B(u_R (r_a),u_R (r_b))]^N + [1/4 B(u_S (s_b),u_S (s_a)) + 1/4 B(u_R (r_a),u_R (r_b))]^N) \
&= cases(
1"," s_a >= s_b "and" r_a >= r_b "and at least one of them strictly holds" \
0.5"," (s_a = s_b "and" r_a = r_b) "or" (s_a > s_b "and" r_a < r_b) "or" (s_a < s_b "and" r_a > r_b) \
0"," "otherwise (that is," s_a <= s_b "and" r_a <= r_b "and at least one of them strictly holds)"
)
$ <ChoiceProb>
You see, the numbering (0.1) overlaps with the long formula:
