How to calculate "6 enters/newlines"

Questions
,
1

Hi.

I have a text with that structure.

#align(center+top)[
Authors Name
]

// 12 * 6 "enter"
// here should be 6 times newlines
#v(72pt)

#align(center+horizon)[
  #text(size: 22pt)[
    *Title*\
  ]
  #v(12pt) // one new line
  #text(size: 18pt)[
    Sub-Title
  ]
]

// 12 * 6 "enter"
// here should be 6 times newlines
#v(72pt)

Text

I hpe that this could be done easily with Relative Length Type – Typst Documentation or Fraction Type – Typst Documentation but I haven’t fully understood which one is here the best.

Maybe this function Measure Function – Typst Documentation is the right solution but I’m not sure how to use it.

Is there a function which can be use in v like the following?

#v(linebreak()*6)
2

Hello!

In Typst, there are two distinct “newlines”: linebreak and parbreak.

The linebreak occurs in a paragraph. The parbreak starts a new paragraph.

In markup, it would look like this:

#lorem(10)\ // linebreak
#lorem(5)

#lorem(10) // parbreak just before! Notice the empty line

If you are trying to get that space between paragraphs, then just create a new empty paragraph 6 times! Calling parbreak multiple times would not work, because consecutive parbreaks are internally collapsed into a single one.

#for i in range(6) { par[] }