$ mus((A inter B) inter C) + mus((A inter B)^c inter C) &= mus((A inter B) inter C) + mus(A inter B^c inter C) + mus(A^c inter C) + 0 + 0 \
&= mus(A inter C) + mus(A^c inter C) = mus(C). $
I would like it to go on a line below so I do this:
$ mus((A inter B) inter C) + mus((A inter B)^c inter C) &= \
mus((A inter B) inter C) + mus(A inter B^c inter C) + mus(A^c inter C) + 0 + 0 \
&= mus(A inter C) + mus(A^c inter C) = mus(C). $
But then it is left-aligned and “pushes” my equation towards the right, so that now the third line overflows:
I added a & on the beginning of the second line. Is this how you want it?
$ mus((A inter B) inter C) + mus((A inter B)^c inter C) &= \
& mus((A inter B) inter C) + mus(A inter B^c inter C) + mus(A^c inter C) + 0 + 0 \
&= mus(A inter C) + mus(A^c inter C) = mus(C). $
What I would like is the second line to be right-aligned independently of the alignment characters in the other lines. Typically what I would like to be working is this:
$ mus((A inter B) inter C) + mus((A inter B)^c inter C) &= \
#h(1fr) mus((A inter B) inter C) + mus(A inter B^c inter C) + mus(A^c inter C) + 0 + 0 \
&= mus(A inter C) + mus(A^c inter C) = mus(C). $
However the #h command does nothing.
Let me mention that I have no idea on how to do that in Latex, as the \hfill command does not work in an align environment.
If I have large formulas overflowing, I typically do something like this:
$ & mus((A inter B) inter C) + mus((A inter B)^c inter C) \
= & mus((A inter B) inter C) + mus(A inter B^c inter C) + mus(A^c inter C) + 0 + 0 \
= & mus(A inter C) + mus(A^c inter C) = mus(C). $
…but I’m not sure if that’s what you want and applicable to your case.
Alternatively, you could use negative spacing with #h and manually position the line where you want it to be. I’m not exactly sure why, but relative types like the fr type doesn’t work here, but absolute types like pt and cm do:
$ mus((A inter B) inter C) + mus((A inter B)^c inter C) &= \
& #h(-100pt) mus((A inter B) inter C) + mus(A inter B^c inter C) + mus(A^c inter C) + 0 + 0 \
&= mus(A inter C) + mus(A^c inter C) = mus(C). $