I need help splitting a table horizontally

[vmartel08]

You can follow the guidance in the post you have identified, which is :

@Y.D.X

Wrapping a columns(2) might helps.

and

@Eric

you can force the table to a specific height by wrapping the whole columns call into a block with a fixed height (and width of 100%).

It works well if you set the good height for the surrounding block or page height.

// Needed to see the header content
#show table.cell.where(y: 0): set text(
  fill: white,
  weight: "bold",
)

#block(
  height: 26%, //adjust depending on page size
  width: 75%, //adjust depending on page size
  stroke: red + 0.5pt, // to see the block temporarily
  columns(2, align(center, table(
    columns: 2,
    align: (x, y) => if x == 0 or y == 0 { left } else { center },
    stroke: (x, y) => (
      left: if y == 0 and x > 0 { white } else { black },
      rest: black,
    ),
    fill: (_, y) => if y == 0 { black } else if y >= 1 { white } else { none },

    table.header([$y$], [$y = sin theta$]),
    [$0º = 0$], [$0$],
    [$30º = pi / 6$], [$.5$],
    [$45º = pi / 4$], [$.70711$],
    [$60º = pi / 3$], [$.86603$],
    [$90º = pi / 2$], [$1$],
    [$120º = 2 pi / 3$], [$.86603$],
    [$135º = 3 pi / 4$], [$.70711$],
    [$150º = 5 pi / 6$], [$.5$],
    [$180º = pi$], [$0$],

    [$210º = 7 pi / 6$], [$-.5$],
    [$225º = 5 pi / 4$], [$-.70711$],
    [$240º = 4 pi / 3$], [$-.86603$],
    [$270º = 3 pi / 2$], [$-1$],
    [$300º = 5 pi / 3$], [$-.86603$],
    [$315º = 7 pi / 4$], [$-.70711$],
    [$330º = 11 pi / 6$], [$-.5$],
    [$360º = 2 pi$], [$0$],
  ))),
)